11p^2-30p+19=0

Solution for 11p^2-30p+19=0 equation:

11p^2-30p+19=0

a = 11; b = -30; c = +19;
Δ = b2-4ac
Δ = -302-4·11·19
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{64}=8$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-30)-8}{2*11}=\frac{22}{22}
=1
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-30)+8}{2*11}=\frac{38}{22}
=1+8/11
$